Find the values of a and b in (3 - ?5) / (3 + 2?5) = (a?5 - b) / 11URGENT!!!!

The given expression

$\frac{3 - \sqrt {5}}{ 3 + 2 \sqrt {5}} = a \sqrt{5} - b$

From LHS

$\frac{3 - \sqrt {5}}{ 3 + 2 \sqrt {5}} \times \frac{3- 2 \sqrt{5}} {3 - 2 \sqrt{5}} \\ = \frac{9 - 6 \sqrt{5} - 3 \sqrt{5} + 2 \times 5}{9 - 20} \\ = \frac{19- 3\sqrt{5}}{-11} \\$

Now it can be written as  and  compared LHS and RHS

$\frac{3 \sqrt{5}}{ 11} - \frac{19}{11} = a\sqrt{5}- b$

Here, a = 3/11 and b = 19/11

Hence,

$a = \frac{3}{11} and , b = \frac{19}{11}$

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