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Find the values of a and b in (3 - ?5) / (3 + 2?5) = (a?5 - b) / 11URGENT!!!!

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The given expression 

                                     $$ frac3 - sqrt 5 3 + 2 sqrt 5 = a sqrt5 - b$$

From LHS 

                      $$ frac3 - sqrt 5 3 + 2 sqrt 5 	imes frac3- 2 sqrt5 3 - 2 sqrt5 $$\$$ $$= frac9 - 6 sqrt5 - 3 sqrt5 + 2 	imes 59 - 20 $$\$$ $$ = frac19- 3sqrt5-11 $$ \ $$

Now it can be written as  and  compared LHS and RHS 

                                                             $$ frac3 sqrt5 11 - frac1911 = asqrt5- b $$

Here, a = 3/11 and b = 19/11

Hence, 

                                                       $$ a = frac311 and , b = frac1911 $$

Posted by

Deependra Verma

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