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Find the value(s) of x, if the distance between the points A(0, 0) and B(x, – 4) is 5 units.

Answers (1)

Distance Formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2- y_1)^2}$

$(x_1, y_1) = (0,0)$ and $(x_2, y_2) = (x,-4)$

$5 = \sqrt{(x-0)^2 + (-4 -0)^2}$

$5 = \sqrt{x^2 + 16}$

Squaring both sides,

$25 = {x^2 + 16} \Rightarrow x^2 = 9$

$x = \pm 3$

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Safeer PP

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