Find the zero of the polynomial and verify the relationship between zeros and coefficient 2âˆš2x^2-9x+5âˆš2â€‹

2√2x2-9x+5√2â€‹ = 0

2√2x2-4x -5x +5√2â€‹ = 0

2√2x(x-√2) -5 ( x- √2) =0

(x-√2)(2√2x-5) = 0

x = √2 or x = 5/2√2

Sum of roots = (-b/a) = 9/2√2

√2 + 5/2√2 =  (4+5)/2√2 = 9/2√2

Product of the roots (c/a) = 5/2

√2 x 5/2√2 = 5/2

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