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Find the zeroes of the quadratic polynomial 4y^2-15 and verify the relationship between the zeroes and the cofficients​

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4y^2-15 = 0 \\ y^2 = \frac{15}{4} \\ y = \pm \frac{\sqrt{15}}{2} \\ $ Sum of the root = - b/a = 0 $ \\ \frac{\sqrt{15}}{2} -\frac{\sqrt{15}}{2} = 0 \\ $ Product of roots = c/a = $\frac{-15}{4} \\ \frac{\sqrt{15}}{2} \times \frac{-\sqrt{15}}{2} = \frac{15}{2}

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Ravindra Pindel

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