# Find the zeroes of the quadratic polynomial 9t^2 - 6t + 1 and verify the relationship between the zeroes and coefficient.

9t2 - 6t + 1 = 0

9t2 - 3t -3t + 1 = 0

3t(3t -1) -1 (3t-1) =0

(3t-1)(3t-1) =0

Both roots are same and = t = 1/3.

Sum of the roots = -b/a = -(-6/9) = 2/3

1/3 + 1/3 = 2/3

Product of roots = (c/a) = 1/9

1/3 x 1/3 = 1/9.

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