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Find the zeros of the quadratic polynomial 6x square - 7 x minus 3 and verify the relation between its zeros and coefficients​

Answers (1)

6x2 - 7x - 3 =0

6x2 - 9x + 2x - 3 =0

3x(2x - 3) +1 (2x-3) =0

(2x-3)(3x+1) =0

x = 3/2 or x = -1/3

Sum of the products (-b/a) = -(-7)/6 = 76

3/2 - 1/3 = (9-2)/6 =7/6

Product of the roots (c/a) = -3/6 = -1/2

3/2 x (-1/3) = -1/2

 

Posted by

Ravindra Pindel

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