Find three consecutive odd integers whose sum is 69.

Answers (1)

Let the smallest of the required consecutive odd integers be x.
Then the next two odd integers are x+2 and x+4.
By the given condition, 
x+(x+2)+(x+4)=69
3x+6=69
3x=69-6
3x=63
x=21
Then, the required consecutive numbers are
21,21+2=23,21+4=25.

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