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Find zeroes of polynomial p(x) = x^2 - x -12 ?

Answers (1)

x2 - x -12 = 0

x2 - 4x + 3x -12 = 0

x ( x -4) + 3 ( x -4) = 0

(x -4 ) ( x +3 ) = 0

x = 4  or  x = - 3

Posted by

Ravindra Pindel

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