# Five point charges, each of charge $+q$ are placed on five vertices of a regular hexagon of side $'l'$. Find the magnitude of the resultant force on a charge $-q$ placed at the centre of the hexagon.

The force due to the charges placed diagonally opposite at the vertices of a hexagon, on the charge $-q$ cancel in pairs.

Hence, the net force is due to one charge only.

Net force $\left | \vec{f} \right |=\frac{1}{4\pi \epsilon _{0}}\; \frac{q^{2}}{l^{2}}$ is on charge $-q$ placed at the centre of the hexagon.

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