Five point charges, each of charge +q are placed on five vertices of a regular hexagon of side 'l'. Find the magnitude of the resultant force on a charge -q placed at the centre of the hexagon.

 

 
 
 
 
 

Answers (1)
S safeer

The force due to the charges placed diagonally opposite at the vertices of a hexagon, on the charge -q cancel in pairs.

Hence, the net force is due to one charge only.

Net force \left | \vec{f} \right |=\frac{1}{4\pi \epsilon _{0}}\; \frac{q^{2}}{l^{2}} is on charge -q placed at the centre of the hexagon.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 6999/- ₹ 5/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout BITSAT 2020

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 1999/-
Buy Now
Exams
Articles
Questions