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  • Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present ages.

Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present ages.

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Five years hence:

Father's age = x+5

Son's age = y+5

Given: x+5 = 3(y+5)

That is x - 3y = 10   ....(1)

 

Five years ago:

Father's age = x - 5

Son's age = y - 5

Given: x - 5 = 7(y - 5)

That is x - 7y = -30   ....(2)

 

Solving the above equations

x = 40 and y = 10

 

SO, the present ages of father and son are 40 and 10

Posted by

Deependra Verma

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