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Foot of the perpendicular of(x, yjonx-axis​

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The given point is (x1, y1).
As we plot the point (x1, y1) in the xy-plane, we go x1 units length on the x-axis.
Then we go vertically upwards or vertically downwards parallel to the y-axis according to y1 being positive or negative respectively.
As we are going upwards or downwards, we can say that we have found a point (x1, 0) on the x-axis and then we plot (x1, y1) by moving vertically.
Therefore the required foot of the perpendicular of the point (x1, y1) on the x-axis is (x1, 0).

Posted by

Satyajeet Kumar

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