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From the following distribution, find the median : 

Classes : 500-600 600-700 700-800 800-900 900-1000
Frequency :  36 32 32 20 30
 

 

 
 
 
 
 

Answers (1)

Classes : 500-600 600-700 700-800 800-900 900-1000
Frequency :  36 32 32 20 30

Cumulative frequency

36 68 100 120 150

N= 150 \implies \frac{N}{2} = 75
Therefore, Median class = 700-800
Frequency corresponding to median class, f = 32
Cumulative frequency of the class preceding the median class, c.f. = 68
Lower limit, l = 700; Class height, h = 100

\begin{aligned} \\ &\begin{aligned} \operatorname{Median} &=l+\frac{\left(\frac{\mathrm{N}}{2}-\mathrm{cf}\right)}{\mathrm{f}} \times \mathrm{h} \\ &=700+\frac{75-68}{32} \times 100 \\ &=721.88 \end{aligned} \end{aligned}

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Safeer PP

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