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  • From the top of a 7m high building, the angle of elevation of the top of a tower is  and the angle of depression of its foot is <img alt="45^{\circ}" s

From the top of a 7m high building, the angle of elevation of the top of a tower is 60^{\circ} and the angle of depression of its foot is 45^{\circ}.
Determine the height of the tower.

 

 

 

 
 
 
 
 

Answers (1)

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In triangle \Delta DBC , 
\\\tan 45^o = \frac{CD}{BD} = \frac{7}{BD} = 1\\ BD =7\ m 
since DB = CE = 7 m

In triangle \Delta ACE ,

\\\tan 60^o = \frac{h}{CE}=\frac{h}{7}=\sqrt{3}\\ \therefore h = 7\sqrt{3}\ m

Thus, the total height of the tower equal to h+7 =7(1+\sqrt{3}\) m

Posted by

Safeer PP

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