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Giv reason for the following:

(a) The only oxidation state shown by Scandium is +3.

(b) \left [ Ti(H_{2}O)_{6} \right ]^{+4} is colourless.

(c) MnO is basic while Mn_{2}O_{7} is acidic.

 

 

 

 
 
 
 
 

Answers (1)

(a) Electronic configuration of Scadium is [Ar]3d^{1}4s^{2}. After donating 3 electrons Scadium exhibits noble gas electronic configuration [Ar] . since to obtain extra stability, Scadium exhibit +3 oxidation state.

(b) The electronic configurataion Ti^{4+} is [Ar]3d^{0}4s^{0}. hence, there is no electron present in d -orbital and hence there is no d-d transition taking placeto impart colour to \left [ Ti(H_{2}O)_{6} \right ]^{+4}.

(c) Oxidation state of Mn in MnO is +2 and hence electronic configuration of Mn^{2+} is [Ar]3d^{5}4s^{0}. Oxidation state of Mn in Mn_{2}O_{7} is +7 and hence electronic configuration of Mn^{7+} is  [Ar]3d^{0}4s^{0}.

Thus, Mn^{2+} being rich in electrons is basic in nature, whereas Mn^{7+} being deficient in electrons is acidic in nature.

Posted by

Sumit Saini

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