Give reason to explain why n and p regions of a Zener diode are heavily doped. Find the current through the Zener diode in the circuit given  below : (Zener breakdown voltage is 15\; V)

 

 
 
 

Answers (1)

n and p regionsof Zener diode is heavily doped so that the depletion region formed is very thin and electric field at the junction is extremely high even for a small reverse bias voltage.

I=\frac{V}{R}

Here, I=\frac{20-15}{250}=\frac{1}{50}=0.2 \; A

Now, the current through the resistor of 1\; K\; \Omega is ;

I=\frac{15}{1000}=0.015\; Ampere

Therefore the current through the Zener diode will be-

I=0.02-0.015

I=0.005\; A

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