Give reasons for the following :

(i) Transition metals form alloys.

(ii) Mn_{2}O_{3} is basic whereas Mn_{2}O_{7} is acidic.

(iii) Eu^{2+} is a strong reducing agent.

 

 

 

 
 
 
 
 

Answers (1)

(i) The size of transition metals are similar size, Therefore, they get easily settled in the      crystal lattice of another metal, hence, they form alloys.

(ii) Mn_{2}O_{3} is bnasic because Mn is +3 and exist in d^{+} electronic configuration.  

    Mn can lose 4 more electron to achieve +7 oxidation state of d^{\circ} state.

    Mn_{2}O_{7} is acidic, because, it already exist in highest horrible oxidn state i.e, +7 and     has no more electrons left to lose. therefore, Mn_{2}O_{7} is acidic

(iii) Eu^{2+} get easily oxidised to Eu^{3+},as Eu^{3+} is more stable, hence Eu^{2+} acts as         strong reducing agent.

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