Give reasons for the following :

(i) Transition metals form alloys.

(ii) Mn_{2}O_{3} is basic whereas Mn_{2}O_{7} is acidic.

(iii) Eu^{2+} is a strong reducing agent.

 

 

 

 
 
 
 
 

Answers (1)
S Sumit

(i) The size of transition metals are similar size, Therefore, they get easily settled in the      crystal lattice of another metal, hence, they form alloys.

(ii) Mn_{2}O_{3} is bnasic because Mn is +3 and exist in d^{+} electronic configuration.  

    Mn can lose 4 more electron to achieve +7 oxidation state of d^{\circ} state.

    Mn_{2}O_{7} is acidic, because, it already exist in highest horrible oxidn state i.e, +7 and     has no more electrons left to lose. therefore, Mn_{2}O_{7} is acidic

(iii) Eu^{2+} get easily oxidised to Eu^{3+},as Eu^{3+} is more stable, hence Eu^{2+} acts as         strong reducing agent.

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