Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Give two solutions of (x^2 +x+1)=0

Answers (1)

$(x^2 +x+1)=0 \\ x = \frac{-1\pm \sqrt{1^2-4 \times 1 \times 1}}{2 \times 1}\\ x = \frac{-1\pm \sqrt{3}i}{2}\\ x = \frac{-1+ \sqrt{3}i}{2}, \ or \ x = \frac{-1- \sqrt{3}i}{2}\\$

Posted by

Ravindra Pindel

View full answer

Similar Questions

Latest Question