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How is displacement current produced between the plates of a parallel plate capacitor during charging ?

 

 
 
 
 
 

Answers (1)

In between the plates of the capacitor due to the time-varying electric field, there is a change in electric flux which constitute a current. This current is known as displacement current. While charging a capacitor total current is the sum of displacement and conduction current.

During charging the charge is varying with time

Therefore change in flux with respect to time

\frac{d\phi_E}{dt}=\frac{dQ}{dt}\frac{1}{\epsilon_0}

\frac{d\phi_E}{dt}=I_d\frac{1}{\epsilon_0}

Displacement current 

I_d=\epsilon_0 \frac{d\phi_E}{dt}

Posted by

Safeer PP

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