How many aluminium atoms are present in 0.051 gram of aluminium oxide?

Answers (1)

Molecular mass of Al2O3 = 27*2 + 16*3 = 102g/mol 

so moles in 0.051 = mass/Mm = 0.051/102 = 0.0005 moles 

2 Al ions per molecule, so 0.001 moles of Al ions 

number of ions = moles x NA where NA is avogadros number = 6.022x10^23 

so number of ions = 6.022x10^23 x 0.001 = 6.022x10^20 ions

 

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