How many randomly assembled people are needed to have a better than 50% probability that at least 1 of them was born in a leap year?A. 1B. 2C. 3D. 4E. 5

ANS:  Lets assume n people are present .

the probability of one person having bday in leap year is 1/4

the probability of n people of which atleast one of them born in leap year = 1 - ( probability of none of them born in leap year )

$\\ \Rightarrow p=1-(3/4)^n > 1/2 \\ \\ \Rightarrow p= (3/4)^n < 1/2$

So when n is 3it will be just less than half.

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