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(i) Out of (CH_{3})_{3}C-Br and (CH_{3})_{3}C-I, which one is more reactive towards S_{N}1 and why?

(ii) Write the product formed when p-nitrochlorobenzene is heated with aqueous NaOH at 443K followed by acidification?

(iii) Why dextro and laevo - rotatory isomers of butan - 2-ol are difficult to seprate by fractional distillation?

 

 

 

 
 
 
 
 

Answers (1)

(i)  (CH_{3})_{3}I, beacuse I^{-} is a better leaving group than Br^{-}.

(ii) 

 

(iii) Dextro and Laevo- rotatory isomers of butan-2-ol are difficult to seprate by fractional distillation due to their identical boiling points.

Posted by

Sumit Saini

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