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  • (i)    Write the structure of the product(s) formed :         (a)    <img alt="\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{COOH}\xrightarrow{\mathrm{Cl}_{2} \text {red phosphor

(i)    Write the structure of the product(s) formed :

        (a)    \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{COOH}\xrightarrow{\mathrm{Cl}_{2} \text {red phosphorus}}

        (b)    \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl} {\xrightarrow {\mathrm{H}_{2}, \mathrm{Pd}-\mathrm{BaSO}_{4}}}

        (c)    2 \mathrm{HCHO} {\xrightarrow{\text { Conc.KOH }}}

(ii)    How will you bring the following conversions in not more than two steps :
        (a) Propanone to propene
        (b) Benzyl chloride to phenyl ethanoic acid

 

 

 

 
 
 
 
 

Answers (1)

(i)        (a)    \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{COOH}\xrightarrow{\mathrm{Cl}_{2} \text {red phosphorus}} CH_3\underset{Cl}{\underset {|}{CH}}-COOH

           (b)   

 \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl} {\xrightarrow {\mathrm{H}_{2}, \mathrm{Pd}-\mathrm{BaSO}_{4}}} C_6H_5-CHO + HCl

           (c) 

   2 \mathrm{HCHO} {\xrightarrow{\text { Conc.KOH }}} HCOO^-Na^+ + CH_3-OH

(ii)    (a) Propanone to propene

                CH_3COCH_3 +NaBH_4\rightarrow CH_3\underset{Cl}{\underset{|}{CH}}-CH_3\xrightarrow{conc.H_2SO_4, \ \Delta} CH_3CH=CH_2
        (b) Benzyl chloride to phenyl ethanoic acid

        

Posted by

Sumit Saini

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