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(i) Write two points to distinguish between interference and diffraction fringes.

(ii) In a Young’s double slit experiment, fringes are obtained on a screen placed a certain distance away from the slits. If the screen is moved by 5\; cm towards the slits, the fringe width changes by 30\; \mu m. Given that the slits are 1\; mm apart, calculate the wavelength of the light used.

 

 

 
 
 
 
 

Answers (1)

(i) \rightarrow Interference pattern has a number of equally speed dark and bright bands. The diffraction pattern has a central maxima and is twice wide as other maxima. Away from the centre intensity of maxima falls.

\rightarrow Diffraction is obtained by superposing two waves originating from each point of a slit.

        the interference pattern is obtained by superposing two waves originating from two narrow slits.

(ii) Given slit width

 d=1mm=10^{-3}m; 

fringe width,

\beta =\frac{\lambda D}{d}

 change in fringe width =30\mu _{m}

    \frac{\lambda D}{d}-\frac{\lambda (D-0.05)}{d}=30\times 10^{-6}m

            \frac{0.05\lambda }{d}=30\times 10^{-6}m

            0.05\lambda =30\times 10^{-9}m

             \lambda =6\times 10^{-7}m

                    =600\; nm

Posted by

Safeer PP

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