If |2x-3|<|x+5| , then x lies in the interval:

Answers (1)

Solution:   We have ,   left | 2x-3 
ight |< left | x+5 
ight |

                   (2x-3)^2< (x+5)^2\ \Rightarrow 3x^2-22x-16< 0,\ \Rightarrow (3x+2)(x-8)< 0\ \Rightarrow hspace1cmxin (frac-23,8).

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