Assume the first term of AP is a and the common difference is d.
ATQ
7(a + 6d) = 11(a + 10d)
7a + 42d = 11a + 110d
4a + 68d = 0
4(a + 17d) = 0
a + 17d = 0 .....(i)
Now
a18 = a + 17d
a18 = 0 { By equation (i)}
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