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If 7 times the 7th term of an AP is equal to 11 times the 11th term, show that the 18th term of it is 0

Answers (1)

Given 7a7 = 11a11

7( a + 6d ) = 11( a + 10d )

 7a + 42d = 11a + 110d 
11a - 7a -42d + 110d=0 
4a + 68d =0

4( a + 17d ) = 0
a + 17d = a18=0

Hence Proved 

Posted by

Ravindra Pindel

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