If y= \sin^{-1}x+\cos^{-1}x,\: find\: \frac{dy}{dx}.

 

 

 

 
 
 
 
 

Answers (1)

given y= \sin^{-1}x+\cos^{-1}x
\Rightarrow \frac{dy}{dx}= \frac{d}{dx}\left ( \sin^{-1}x+\cos^{-1}x \right )
= \frac{d}{dx}\left ( \sin^{-1}x \right )+\frac{d}{dx}\left ( \cos^{-1}x \right )
\Rightarrow \frac{1}{\sqrt{1-x^{2}}}-\frac{1}{\sqrt{1-x^{2}}}= 0
\therefore \frac{dy}{dx}= 0

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