Knockout NEET July 2020
An exhaustive E-learning program for the complete preparation of NEET..
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given:
![\log \left ( \sin x \right )\frac{dy}{dx}+y\frac{d}{dx}\left [ \log \left ( \sin x \right ) \right ]= \frac{d}{dx}\left [ \log \left ( x+y \right ) \right ]](https://entrancecorner.codecogs.com/gif.latex?%5Clog%20%5Cleft%20%28%20%5Csin%20x%20%5Cright%20%29%5Cfrac%7Bdy%7D%7Bdx%7D+y%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%20%5B%20%5Clog%20%5Cleft%20%28%20%5Csin%20x%20%5Cright%20%29%20%5Cright%20%5D%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%20%5B%20%5Clog%20%5Cleft%20%28%20x+y%20%5Cright%20%29%20%5Cright%20%5D)
![\Rightarrow \frac{dy}{dx}\left [ \log \left ( \sin x \right ) -\frac{1}{\left ( x+y \right )}\right ]= \frac{1}{\left ( x+y \right )}-y\cdot \cot x](https://entrancecorner.codecogs.com/gif.latex?%5CRightarrow%20%5Cfrac%7Bdy%7D%7Bdx%7D%5Cleft%20%5B%20%5Clog%20%5Cleft%20%28%20%5Csin%20x%20%5Cright%20%29%20-%5Cfrac%7B1%7D%7B%5Cleft%20%28%20x+y%20%5Cright%20%29%7D%5Cright%20%5D%3D%20%5Cfrac%7B1%7D%7B%5Cleft%20%28%20x+y%20%5Cright%20%29%7D-y%5Ccdot%20%5Ccot%20x)
