Solution :
( k +1 ) tan^2 x - 2^1/2 p tanx = 1 - k
tan^2 (a + b) = 50
Now ,
⇒ tan a + tan b = 2^1/2 p / p + 1 , tan a tan b =( p - 1) / ( p + 1)
⇒ [ ( 2 ^ 1/ 2 p) / ( k + 1) / 1 - ( k -1) /( k + 1) ]
⇒ 2 p^2 / 4 = 50
⇒ p^2 = 100
⇒ p =10 Ans
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