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If (A, B) are the coordinates of the midpoint of line segment joining the points (2,1) and (1,-3). Find the value of 3A^2+2AB+B^2.

Answers (1)

(A,B) = ((2+1)/2, (1-3)/2)

(A.B) = (3/2,-1)

3A2+2AB+B2 = 3 (3/2)2 +2 x 3x(-1)/2+1

                      = 27/4 - 3 +1 

                     = 19/4

Posted by

Ravindra Pindel

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