# If a/b=25/6, then find the value of (a^2-b^2)/(a^2+b^2)

Given,
$\frac{a}{b}=\frac{25}{6}$
Squaring both sides,we get
$\frac{a^{2}}{b^{2}}=\frac{25^{2}}{6^{2}}$
Subtracting $b^{2}$, from numerator and adding $b^{2}$ to the denomenator,we get
$\frac{a^{2}-b^{2}}{a^{2}+b^{2}}\Rightarrow \frac{25^{2}-6^{2}}{25^{2}+6^{2}}$
$\frac{625-36}{625+36}=\frac{589}{661}$

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