get app

Go To Your Study Dashboard

If a/b=25/6, then find the value of (a^2-b^2)/(a^2+b^2)

Answers (1)

D Deependra Verma

Given,
$fracab=frac256$
Squaring both sides,we get
$fraca^2b^2=frac25^26^2$
Subtracting $b^2$ , from numerator and adding $b^2$ to the denomenator,we get
$fraca^2-b^2a^2+b^2Rightarrow frac25^2-6^225^2+6^2$
$frac625-36625+36=frac589661$

Similar Questions

Please solve RD Sharma Class 12 Chapter 28 The Plane Exercise 28.9 Question 13 maths textbook solution. Q.
Please solve RD Sharma Class 12 Chapter 28 The Plane Exercise 28 .9 Question 12 maths textbook solution. Q.
Please solve RD Sharma Class 12 Chapter 28 The Plane Exercise 28.9 Question 11 maths textbook solution. Q.
Need solution for RD Sharma maths Class 12 Chapter 28 The Plane Exercise 28.9 Question 10 textbook solution. Q.
Need solution for RD Sharma maths Class 12 Chapter 28 The Plane Exercise 28.9 Question 9 textbook solution. Q.

Latest Asked Questions

Most Viewed Questions

Preparation Products

Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 40000/-

Buy Now

Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-

Buy Now

NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-

Buy Now

NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-

Buy Now

NEET Foundation + Knockout NEET 2025 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-

Buy Now

Boost your Preparation for JEE Main with our Foundation Course

Start Now

Exams

Articles

Questions