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  • If a/b=25/6, then find the value of (a^2-b^2)/(a^2+b^2)

If a/b=25/6, then find the value of (a^2-b^2)/(a^2+b^2)

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best_answer

Given,
fracab=frac256
Squaring both sides,we get
fraca^2b^2=frac25^26^2
Subtracting b^2, from numerator and adding b^2 to the denomenator,we get
fraca^2-b^2a^2+b^2Rightarrow frac25^2-6^225^2+6^2
frac625-36625+36=frac589661

Posted by

Deependra Verma

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