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  • If alpha and beta be the roots of ax^2+bx+c =0 ; then slove Limit of (1+ax^2+bx+c)^2/x-alpha As x--> alpha

If alpha and beta be the roots of ax^2+bx+c =0 ; then slove Limit of (1+ax^2+bx+c)^2/x-alpha As x--> alpha

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Solution:     We have ,

                      ax^2+bx+c=0 and alpha ,eta  Be the root of the equation 

                    lim_x o alpha(1+ax^2+bx+c)^frac2x-alpha

We have , given limit        =lim_x oalpha [1+a(x-alpha)(x-eta)]^frac2x-alpha

                                            =e^lim_x oalpha a(x-alpha)(x-eta)^frac2x-alpha=e^2a(alpha-eta)      

Posted by

Deependra Verma

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