if f\left ( x \right )= x+7 and g\left ( x \right )= x-7,x\epsilon R then find \frac{d}{dx}\left ( fog \right )\left ( x \right )

 

 

 

 
 
 
 
 

Answers (1)

given:f\left ( x \right )= x+7
and g\left ( x \right )= x-7  find  \frac{d}{dx}\, fog\left ( x \right )
fog\left ( x \right )= f\left ( g\left ( x \right ) \right )
= f\left ( x-7 \right )
\Rightarrow x-7+7
\Rightarrow x
now differentiating w.r.t to x we get
\frac{d}{dx}\, fog\left ( x \right )= 1

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