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If one of the zeroes of the quadratic polynomial (k – 1)x^2 + kx +1 is 1 then the value of k is

Answers (1)

P(x) =  (k – 1)x2 + kx +1

P(1) =  (k – 1)12 + k +1 = 0

k-1 + k + 1 = 0

2k = 0

k = 0

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Ravindra Pindel

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