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Dividing f(x) = ax3+3x2-3 by x-4, So put x=4 in the equation and we will get the remainder as 45 + 64 a
Dividing 2x3-5x+a by x-4, So put x=4 in the equation and we will get the remainder as a+108
Accordinng to the question, a + 108 = 45 + 64 a
63 a = 63
a = 1