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If R is the radius of the circumcircle of the triangle ABC and delta is its area , then

Answers (1)

D Deependra Verma

Solution: Area of the triangle ,

$ABC(Delta )=fracbc2sin A.$ From the sine formula ,

$a=2Rsin ARightarrow sin A=fraca2R .$

$Rightarrow$ $Delta =frac12bc.fraca2R=fracabc4RRightarrow R=fracabc4Delta .$

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