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If secA=5/4 then tanA/1+tansquare?

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Solution : Given   

SecA = 5 / 4 , then Find the value of   tanA / ( 1+ tan^2A) 

We know  ,     1 + tan^2A = Sec^2A 

⇒     1 + tan^2A =(5 /4)^2  

⇒   tan^2A =(25 /16) - 1

⇒  tan^2A  = 9/ 16

⇒  tanA =3/4

Hence   

           ⇒    tanA /( 1 + tan^2A )= ( 3 / 4 ) /( 25 / 16) =12 /25  Ans

Posted by

Deependra Verma

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