If secA=5/4 then tanA/1+tansquare​ A is a 25/12 b 16/25 c 12/25 d 9/16

Answers (1)
S safeer

We know that

\\sec^2A-tan^2A=1 \\Given \ sec A = 5/4\\sec^2A=25/16 \\There fore \\tan^2A=sec^A-1=\frac{25}{16}-1=\frac{9}{16}\\tanA=\sqrt{\frac{9}{16}}=\frac{3}{4} (taking\ only\ positive \ values)

Therefore

\frac{tanA}{1+tan^2A}=\frac{tanA}{sec^A}=\frac{\frac{3}{4}}{\frac{25}{16}}=\frac{12}{25}

Preparation Products

Knockout KCET 2021

An exhaustive E-learning program for the complete preparation of KCET exam..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout KCET JEE Main 2021

It is an exhaustive preparation module made exclusively for cracking JEE & KCET.

₹ 27999/- ₹ 16999/-
Buy Now
Knockout NEET Sept 2020

An exhaustive E-learning program for the complete preparation of NEET..

₹ 15999/- ₹ 6999/-
Buy Now
Rank Booster NEET 2020

This course will help student to be better prepared and study in the right direction for NEET..

₹ 9999/- ₹ 4999/-
Buy Now
Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Exams
Articles
Questions