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  • if sin a +cos a=p, sec a+cosec a=q then show that q(p2-1)=2p

if sin a +cos a=p, sec a+cosec a=q then show that q(p2-1)=2p

Answers (1)

sina + cosa =p => (sina +cosa)2= sin2 a + cos2 a + 2 sina x cosa = 1+ 2sina x cosa = p2

p2-1= 2 sina x cosa

Now  q(p2-1) = (seca + coseca)2 sina x cosa = [1/cosa + 1/sina ] 2 sina x cosa = 2 (sina + cosa) = 2 p = RHS

Hence proved

Posted by

Ravindra Pindel

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