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If the common difference of an A.P. is 3, then find a20 – a15

Answers (1)

Given d =3

Nth term of AP

a= a(n − 1)d

a20 – a15 = [a + (20 – 1)d] – [a + (15 – 1)d]

              = 19d – 14d

              = 5d

              = 5 × 3

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Ravindra Pindel

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