If the line ax+y=c, touches both the curves x^2+y^2=1 and y^2=4squre root 2x, then mod c is equal to:

Answers (1)

Solution:  Tangent on \ y^2=4sqrt2x is \ yt=x+sqrt2t^2

As it is tangent on circle also, 

\Rightarrow left | sqrt2t^2/sqrt1+t^2 
ight |=1\ \Rightarrow 2t^4=1+t^2 ;ie;t^2=1

Equation is \pm y=x+sqrt2

hence \left | c 
ight |=sqrt2

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