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  • If the numbers n – 2, 4n – 1 and 5n +2 are in AP, then the value of n is:

If the numbers n – 2, 4n – 1 and 5n +2 are in AP, then the value of n is:

Answers (1)

Given, n – 2, 4n – 1, 5n + 2 are in A.P

So,  2 (4n – 1) = n – 2 + 5n + 2

  8n – 2 = 6n

  2n = 2

 n = 1

Posted by

Ravindra Pindel

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