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  2. If the point ( a , b ) is equidistant from (3, –4) and (8, –5), show that 5 a - b - 32=0
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If the point ( a , b ) is equidistant from (3, 4) and (8, 5), show that 5 a - b - 32=0

Answers (1)
S safeer

Given that (a,b) is equidistant from the points (3, –4) and (8, –5), To show that 5 a - b - 32=0

Therefore

\\(3-a)^2+(4+b)^2=(8-a)^2+(5+b)^2\\9-6a+16+8b=64-16a+25+10b\\10a-2b-64=0\\5a-b-32=0

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