If the sum of first four terms of an AP is 40 and that of first 14 terms is 280. Find the sum of it's first n terms.
Sum of n terms in AP
According to the statements given,
Sum of first four terms
........(1)
Sum of first fourteen terms
........(2)
Subtracting eqn(2) from eqn(1)
2a+3d-2a-13d=20-40
-10d=-20
d=2.
Putting d in eqn (1)
2a+3(2)=20
2a+6=20
2a=14
a=7
Sum of n numbers of AP