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IF x = 2-y, then show that x³+6xy+y³-8=0

Answers (1)

Given : x = 2-y   Cube on botn side

x3 =( 2-y )3  

x3 =23-y3 - 3(2)(y)(2-y)  { (2-y) =x }

x3 =8-y3 - 6yx

x3 + y3 + 6xy -8 = 0

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Ravindra Pindel

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