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If x and [x] denote the fractional and the Integral parts respectively of a real number x , then the period of the fuction f(x)=e^sinx + cos (pi/2) [x] is

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Solution:        x=x-[x]Rightarrow pd(x)=1

                      Rightarrow             pd(e^sin x)=1.

                    Moreover ,    pd[cos (fracpi2[x])]=frac2pifracpi2=4.

                      Rightarrow       pd(f)=LCM1,4=4.                                                   

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Deependra Verma

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