If y=sec(tan^-1x) then dy/dx

Answers (1)

Solution:   We have ,    y=sec(	an^-1x)

   Then ,      y=sec(	an^-1x)=sec(sec^-1fracsqrt1+x^21)=sqrt1+x^2

   \ \ Rightarrow hspace1cmy=sqrt1+x^2\ \ Rightarrow hspace1cm fracmathrmd ymathrmd x=frac12sqrt1+x^2	imes (2x)=fracxsqrt1+x^2

                 

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