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  • If y=x^-1/2+log5 (x)+sinx/cosx+2^x , then dy/dx

If y=x^-1/2+log5 (x)+sinx/cosx+2^x , then dy/dx

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Solution: Here , y=x^-1/2+log_5x+tanx+2^x

On diffrentiating ,we get

fracmathrmd ymathrmd x=(-1/2)x^-3/2+1/xlog_e5+sec^2x+2^xlog_e2

Posted by

Deependra Verma

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