In a triangle ABC , A>B . If A and B satisfy the equation 3sinx -4sin^3x -k=0 ,0
Answers (1)

Solution:    We have ,   3sin x -4sin^3x-k=0    0< k< 1.

                   sin 3A=sin 3B=k     Rightarrow   3A=pi-3B

             Rightarrow      A+B=fracpi3Rightarrow C=frac2pi3.   

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