In a triangle ABC, if a=6,b=3 and cos(A-B)=4/5, the area of triangles is

Answers (1)

Solution:   

                cos (A-B)=frac45      Rightarrow      	an(fracA-B2)=frac13

              fraca-ba+b=	an (fracA-B2)	anfracC2Rightarrow C=90^circ

    Rightarrow              Delta =9 sq.unit

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